Consider the following reduction processes:
$Z n^{2 +} + 2 e^{-} \to Zn (s); E ° = - 0.76 V$
$C a^{2 +} + 2 e^{-} \to Ca (s); E ° = - 2.87 V$
$M g^{2 +} + 2 e^{-} \to Mg (s); E ° = - 2.36 V$
$N i^{2 +} + 2 e^{-} \to Ni (s); E ° = - 0.25 V$
The reducing power of the metals increases in the order.

Question

Consider the following reduction processes:

Z n^{2 +} + 2 e^{-} \to Zn (s); E ° = - 0.76 V

C a^{2 +} + 2 e^{-} \to Ca (s); E ° = - 2.87 V

M g^{2 +} + 2 e^{-} \to Mg (s); E ° = - 2.36 V

N i^{2 +} + 2 e^{-} \to Ni (s); E ° = - 0.25 V

The reducing power of the metals increases in the order.

Accepted Answer

Correct answer: B. (b) Higher the oxidation potential, higher will be the reducing power. So, the order of reducing behavior is: Ca > Mg > Zn > Ni

$Consider the following reduction processes: Z n^{2 +} + 2 e^{-} \to Zn (s); E ° = - 0.76 V C a^{2 +} + 2 e^{-} \to Ca (s); E ° = - 2.87 V M g^{2 +} + 2 e^{-} \to Mg (s); E ° = - 2.36 V N i^{2 +} + 2 e^{-} \to Ni (s); E ° = - 0.25 V The reducing power of the metals increases in the order.$