The exact volumes of 1 MNaOH solution required to neutralise 50 mL of 1 MH_3 PO_3 solution and 100 mL of 2 MH_3 PO_2 solution, respectively, are:

Question

Accepted Answer

Correct answer: C. (c) H_3 PO_3+2 NaOH Na_2 HPO_3+2H_2O 50 ml^31M 1 MV= ? ⇒ n_ NaoHn_H_1 PO_3= 21 ⇒ 1 V50 1= 21 ⇒V_ NaOH=100 ml H_3 PO_2+2 NaOH NaH_2 PO_3+H_2O 100 ml 2M V= ? ⇒ n_ Nandn_H , PO ,= 1l ⇒ 1 V2 100= 11 ⇒V_ NaOH=200 ml

$The exact volumes of 1 MNaOH solution required to neutralise 50 mL of 1 MH_{3} PO_{3} solution and 100 mL of 2 MH_{3} PO_{2} solution, respectively, are:$

Solution

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