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JEE · NEET Previous Year Question

$Xenon reacts with fluorine at 873 K and 7 bar to form XeF_{4} . In this reaction, the ratio of xenon and fluorine required is$

Topic: JEE PYQ

Answer: A. Full step-by-step solution below.

A $1 : 5$
B $10 : 1$
C $1 : 3$
D $5 : 1$

Correct answer: A

Solution

(a) XeF_{4} is obtained by heating a mixture of xenon and fluorine in the molar ratio of 1 : 5 at 873 K and 7 bar pressure.

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