In A_xB_y crystal structure, A atoms occupied all octahedral as well as all tetrahedral voids and B atoms are at FCC centres. What is the formula of compound A_xB_y.

Question

Accepted Answer

Correct answer: D. (d) Number of octahedral voids =x (where x= total number of atoms in the unit cell) Number of tetrahedral Voids =2x ⇒ Total number of 'A' atoms =x+2x=3x Since all 'B' atoms occupy all the FCC centres:- ⇒ Total number of 'B' atoms =(6 12)+(8 18)=4 ⇒x=4 so number of ' A ' atoms =3x=3 4=12 So, the formula will be A_12B_4 or A_3B

$In A_{x} B_{y} crystal structure, A atoms occupied all octahedral as well as all tetrahedral voids and B atoms are at FCC centres. What is the formula of compound A_{x} B_{y} .$

Solution

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