If the radius of an atom of an element which forms a body centred cubic unit cell is 173.2 pm, the volume of unit cell in cm^3 is

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Accepted Answer

Correct answer: B. (b) Given, Radius of an atom (bcc) =173.2 pm ,=1.732 10^-8 cm ∵ For bcc structure 3 .a=4r where, a= edge-length r= radius of atom. and a^3=V (volume of cubic unit cell). ∴=a 4 3 .ra= 41.73 1.732 10^-8 cma=4 10^-8 cm Therefore, Volume (V )= (a^3 )= (10^-8 )^3 4^364 10^-24 cm^3 ⇒6.4 10^-23 cm^3

$If the radius of an atom of an element which forms a body centred cubic unit cell is 173.2 pm, the volume of unit cell in cm^{3} is$

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