A cube of edge length 1 cm is divided into smaller cubes of uniform size of length 1 nm. Assuming that no voids are present, the ratio of total surface area of all the cubes of 1 nm edge length to th…

Question

A cube of edge length 1 cm is divided into smaller cubes of uniform size of length 1 nm. Assuming that no voids are present, the ratio of total surface area of all the cubes of 1 nm edge length to the surface area of the initial cube is

Accepted Answer

Correct answer: B. (b) Surface Area of large cube = (1 cm )^2= (10^7 )^2 nm^2 Surface Area of small cube =1 nm^2 No. of small cubes = volume of large cube volume of small cube= (10^7 )^3 nm^31 nm^3 Ratio of total surface area = No . of small cubes S .A . of small cubesS .A . of large cubes = (10^7 )^3 1 (10^7 )^2=10^7

$A cube of edge length 1 cm is divided into smaller cubes of uniform size of length 1 nm . Assuming that no voids are present, the ratio of total surface area of all the cubes of 1 nm edge length to the surface area of the initial cube is$

Solution

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