In a A_xB_y crystal structure, A^+y ions occupy all the tetrahedral voids and B^-x ions make BCC unit cell. What is the formula of the compound?

Question

Accepted Answer

Correct answer: A. (a) Number ofA^+y ions=2 number of atoms per unit cell . Number ofB^-x ions=2 ( BCC ) per unit cell . ⇒ Number ofA^+y ions=2 2=4 ⇒ Formula=A_4 B_2

$In a A_{x} B_{y} crystal structure, A^{+ y} ions occupy all the tetrahedral voids and B^{- x} ions make BCC unit cell. What is the formula of the compound?$

Solution

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