A 6 \% solution of urea is isotonic with

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Correct answer: D. (d) : When a solution of urea ( 6 \% ) is isotonic with a solution of glucose, _ glucose= _ urea ⇒C_ glucose=C_ urea ∴ ( w_g 1000m_g 100 )= ( w_u 1000m_u 100 ) where, w_g= mass of glucose =x g m_g= molecular mass of glucose = rsO w_u= mass of urea =6 g m_u= molecular mass of urea =60 ∴ x 1000180 100= 6 100060 100 ⇒x=18 g Thus, 18 g of glucose are present in 100 mL of solution. In other words, 1M solution of glucose 18 g in 100 mL ) is isotonic with 6 \% solution of urea.

$A 6 % solution of urea is isotonic with$

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