The coagulation of 200 ml of a positive colloid took place when 0.73 g of HCl was added to it without changing the volume much. The flocculation value of HCl for the colloid is

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Correct answer: D. (d) 200 mL of sol =0.73 gHCl mmol of HCl= 0.73 g36.5 g/ mol=20 mmol 100 mL of sol require = 1000200 20=100 mmol. Therefore, the flocculation value of HCl for the colloid is 100.

$The coagulation of 200 ml of a positive colloid took place when 0.73 g of HCl was added to it without changing the volume much. The flocculation value of HCl for the colloid is$

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