Given that C+O_2 CO_2 , H^o=- xkJ 2 CO+O_2 2CO_2 , H^o=- ykJ The enthalpy of formation of carbon monoxide will be

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Correct answer: A. (a) C_ (s )+O_2 (g ) CO_2 (g ) ; H=- xkJ (i) CO_ (g )+ 12O_2 (g ) CO_2 (g ) ; H=- y2 kJ (ii) By substracting equation (ii) from (i) we get, C_ (s )+ 12O_2 (g ) CO_ (g ); H=-x- (- y2 )= y-2x2 kJ

$Given that C + O_{2} \to C O_{2}, Δ H^{o} = - xkJ 2 CO + O_{2} \to 2 C O_{2}, Δ H^{o} = - ykJ The enthalpy of formation of carbon monoxide will be$

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