In a series LR circuit XL = R and power factor of the circuit is P_l. When capacitor with capacitance C such that XL = X_c is put in series, the power factor becomes P_2. The ratio P_1P_2 is

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Correct answer: B. (b) In case of L-R circuit Z= X_L^2+R^2& power factor P_1= cos = RZ As X_L=R ⇒Z= 2R ⇒P_1= R 2R ⇒P_1= 1 2 In case of L-C-R circuit Z= R^2+(X_L-X_C)^2 As X_L=X_C ⇒Z=R ⇒P_2= cos = RR=1 ⇒ P_1P_2= 1 2

$In a series LR circuit XL = R and power factor of the circuit is P_{l} . When capacitor with capacitance C such that XL = X_{c} is put in series, the power factor becomes P_{2} . The ratio \frac{P _{1}}{P _{2}} is$

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