A capacitance of ( 10^-32 )F and an inductance of ( 100 ) mH and a resistance of 10 are connected in series with an AC voltage source of 220 V ,50 Hz. The phase angle of the circuit is

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Correct answer: C. (c) Capacitance of circuit, C= 10^-32 F Inductance of circuit, L= ( 100 ) mH= 100 10^-3H Frequency of source, f=50 Hz Resistance of circuit, R=10 Inductive impedance, X_L= ωL=2 πfL ⇒X_L=2 50 100 10^-3=10 Capacitive impedance, _C = 1 ωC= 12 πfC = 1 2 2 50 10^-3 = 1005=20 Voltage of source =220 volt Phase angle is given by, tan = X_L-X_CR ⇒ tan ⁡ = X_C-X_LR= 20-1010=1 ⇒ =45^

$A capacitance of (\frac{10 ^{- 3}}{2 π}) F and an inductance of (\frac{100}{π}) mH and a resistance of 10Ω are connected in series with an AC voltage source of 220 V, 50 Hz . The phase angle of the circuit is$

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