JEE · NEET Previous Year Question
A capacitor of capacitance 150.0F is connected to an alternating source of emf given by E = 36 sin(120) V. The maximum value of current in the circuit is approximately equal to:
Topic: JEE PYQ
Answer: A. Full step-by-step solution below.
- A
- BA
- C2 A
- DA
Correct answer: A
Solution
(a) The formula for maximum current is given by= CVm ...(i)
The given data is
= 120
Vm= 36V
C = 150F
Substituting the values in equation (i)
= 2.036A 2A
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