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JEE · NEET Previous Year Question

$The radius of electron's second stationary orbit in Bohr's atom is R. The radius of 3rd orbit will be$

Topic: JEE PYQ

Answer: B. Full step-by-step solution below.

A $\frac{R}{3}$
B $2.25R$
C $3R$
D $9R$

Correct answer: B

Solution

(b) r = 0.529 \times \frac{n ^{2}}{z} r \propto n^{2} R \propto (2)^{2} \dots (1) R_{1} \propto (3)^{2} \dots . (2) Divide (1) by (2) \frac{R _{1}}{R} = \frac{4}{9} R_{1} = \frac{9 R}{4} R_{1} = 2.25 R

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