Two electrons are moving in orbits of two hydrogen like atoms with speeds 3 10^5 m/s and 2.5 10^5 m/s respectively. If the radii of these orbits are nearly same then the possible order of energy stat…

Question

Two electrons are moving in orbits of two hydrogen like atoms with speeds 3 10^5 m/s and 2.5 10^5 m/s respectively. If the radii of these orbits are nearly same then the possible order of energy states are \_ \_ \_ \_ respectively.

Accepted Answer

Correct answer: D. (d) For hydrogen-like atoms: V ∝ Zn and r ∝ n^2Z Thus r ∝ nV Since the radii are nearly the same: n_1V_1= n_2V_2 n_1n_2= V_1V_2= 3 10^52.5 10^5= 65Possible order of energy states is 6 and 5.

$Two electrons are moving in orbits of two hydrogen like atoms with speeds 3 \times 10^{5} m / s and 2.5 \times 10^{5} m / s respectively. If the radii of these orbits are nearly same then the possible order of energy states are____respectively.$

Solution

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