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JEE · NEET Previous Year Question

$If radius of the_{12}^{27} Al nucles is taken to be R_{Al} then the radius of_{53}^{125} Te nucleus is nearly :$

Topic: NEET PYQ

Answer: A. Full step-by-step solution below.

A $\frac{5}{3} R_{AI}$
B $\frac{3}{5} R_{AI}$
C $(\frac{13}{53})^{1/3} R_{AI}$
D $(\frac{53}{13})^{1/3} R_{Al}$

Correct answer: A

Solution

(a) Radius of the nucleus is given by R = R_{0} A^{1/3} \Rightarrow R \propto A^{1/3} ∴ \frac{R _{Al}}{R _{Te}} = (\frac{A _{Al}}{A _{Te}})^{1/3} = (\frac{27}{125})^{1/3} = \frac{3}{5} R_{Te} = \frac{5}{3} R_{Al}

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