A parallel plate capacitor with pates of area 1 m^2 each, are at a separation of 0.1 m. If the electric field between the plates is 100 N/C, the magnitude of charge on each plate. (Take Î_0 = 8.85 ×…

Question

A parallel plate capacitor with pates of area 1 m^2 each, are at a separation of 0.1 m. If the electric field between the plates is 100 N/C, the magnitude of charge on each plate. (Take Î_0 = 8.85 × 10^–12 C^2N−m^2)

Accepted Answer

Correct answer: D. (d) E= σε_0= QA ε_0=100 V/m Q = 100 × A ε_0 Þ Q = 100 × 1 × 8.85 × 10^–12 C = 8.85 × 10^–10 C

$A parallel plate capacitor with pates of area 1 m^{2} each, are at a separation of 0.1 m. If the electric field between the plates is 100 N/C, the magnitude of charge on each plate. (Take I^_{0} = 8.85 \times 1 0^{-12} \frac{C ^{2}}{N - m ^{2}})$

Solution

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