Two metallic plates form a parallel plate capacitor. The distance between the plates is 'd'. A metal sheet of thickness d2 and of area equal to area of each plate is introduced between the plates. Wh…

Question

Two metallic plates form a parallel plate capacitor. The distance between the plates is 'd'. A metal sheet of thickness d2 and of area equal to area of each plate is introduced between the plates. What will be the ratio of the new capacitance to the original capacitance of the capacitor?

Accepted Answer

Correct answer: A. (a) C_1= ∈_0Ad C_2= ∈_0A d2+ d2 ∝= 2 ∈_0Ad C_2C_1= 21

$Two metallic plates form a parallel plate capacitor. The distance between the plates is 'd'. A metal sheet of thickness \frac{d}{2} and of area equal to area of each plate is introduced between the plates. What will be the ratio of the new capacitance to the original capacitance of the capacitor?$

Solution

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