Consider the combination of 2 capacitors C_1 and C_2, with C_2C_1, when connected in parallel, the equivalent capacitance is 154 times the equivalent capacitance of the same connected in series. Cal…

Question

Consider the combination of 2 capacitors C_1 and C_2, with C_2>C_1, when connected in parallel, the equivalent capacitance is 154 times the equivalent capacitance of the same connected in series. Calculate the ratio of capacitors, C_2C_1

Accepted Answer

Correct answer: D. (d) JEE Main 2021 C_1+C_2= 154 ( C_1C_2C_1+C_2 ) 4(C_1+C_2)^2=15C_1C_2 4C_1^2+4C_2^2-7C_1C_2=0 4+4 ( C_2C_1 )^2-7 C_2C_1=0 4 ( C_2C_1 )^2-7 C_2C_1+4=0 C_2C_1has not real value C_2C_1= imaginary

$Consider the combination of 2 capacitors C_{1} and C_{2}, with C_{2} > C_{1}, when connected in parallel, the equivalent capacitance is \frac{15}{4} times the equivalent capacitance of the same connected in series. Calculate the ratio of capacitors, \frac{C _{2}}{C _{1}}$

Solution

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