A particle of mass 10 g moves along a circle of radius 6.4 cm with a constant tangential acceleration. What is the magnitude of this acceleration if the kinetic energy of the particle becomes equal t…

Question

A particle of mass 10 g moves along a circle of radius 6.4 cm with a constant tangential acceleration. What is the magnitude of this acceleration if the kinetic energy of the particle becomes equal to 8 × 10^–4 J by the end of the second revolution after the beginning of the motion ?

Accepted Answer

Correct answer: B. (b) W_all = KE ­ (ma_t)(s) = 12mv^2 (10 × 10^–3)(a_t) (4π × 6.4 × 10^–2) = 8 × 10^–4 Þ a_t = 0.1 m/s^2

$A particle of mass 10 g moves along a circle of radius 6.4 cm with a constant tangential acceleration. What is the magnitude of this acceleration if the kinetic energy of the particle becomes equal to 8 \times 1 0^{-4} J by the end of the second revolution after the beginning of the motion ?$

Solution

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