A 1 kg ball moving with a speed of 6 ms^-1 collides headon with a 0.5 kg ball moving in the opposite direction with a speed of 9 ms^-1. If the coefficient of restitution is 13, then the energy lost i…

Question

A 1 kg ball moving with a speed of 6 ms^-1 collides headon with a 0.5 kg ball moving in the opposite direction with a speed of 9 ms^-1. If the coefficient of restitution is 13, then the energy lost in the collision is

Accepted Answer

Correct answer: C. (c) Using KE= m_1m_22(m_1+m_2)(1-e^2)(u_1+u_2)^2 Given: m_1=1 kg m_2= 12 kgu_1=6 ms^-1 and u_2=9 ms^-1 and e= 13 ∴ KE= 1 122(1+ 12)(1- ( 13 )^2) (6+9 )^2= 12 26 89 (15 )^2= 16 89 225=33.33 J

$A 1 kg ball moving with a speed of 6 ms^{- 1} collides headon with a 0.5 kg ball moving in the opposite direction with a speed of 9 ms^{- 1} . If the coefficient of restitution is \frac{1}{3}, then the energy lost in the collision is$

Solution

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