When three identical bulbs of 60 watt, 200 volt rating are connected in series to a 200 volt supply, the power drawn by them will be

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Correct answer: D. (d) The resistance of each bulb = V^2P= (200 )^260 When three bulbs are connected in series their resultant resistance = 3 (200 )^260 . Thus power drawn by bulb when connected across 200 V supply P= V^2R_ ve= (200 )^23 (200 )^2/60=20 W.

$When three identical bulbs of 60 watt, 200 volt rating are connected in series to a 200 volt supply, the power drawn by them will be$

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