Current Electricity PYQs Set 16 (PDF)

Set 16 of 21 · Questions 451-480 of 612

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Mere Teacher · Previous Year Questions NEET Physics · Current Electricity · Set 16 (Q451-480)
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451. $See the electrical circuit shown in this figure. Which of the following equations is a correct equation for it?$ (1) $ϵ_{2} - i_{2} r_{2} - ϵ_{1} - i_{1} r_{1} = 0$ (2) $- ϵ_{2} - (i_{1} + i_{2}) R + i_{2} r_{2} = 0$ (3) $ϵ_{1} - (i_{1} + i_{2}) R + i_{1} r_{1} = 0$ (4) $ϵ_{1} - (i_{1} + i_{2}) R - i_{1} r_{1} = 0$ 452. $As shown in the figure, a network of resistors is connected to a battery of 24 V with an internal resistance of 3 Ω . The currents through the resistors R_{4} and R_{5} are I4 and I5 respectively. The values of I4 and I5 are;$ (1) $I_{4} = \frac{8}{5} and I_{5} = \frac{2}{5} A$ (2) $I_{4} = \frac{24}{5} A and I_{5} = \frac{6}{5} A$ (3) $I_{4} = \frac{6}{5} and I_{5} = \frac{24}{5} A$ (4) $I_{4} = \frac{2}{5} A and I_{5} = \frac{8}{5} A$ 453. $Two cells of emf E_{1} and E_{2} are joined in opposition (such that E_{1} > E_{2}). If r_{1} and r_{2} be the internal resistance and R be the external resistance, then the terminal potential difference is$ (1) $\frac{E _{1} + E _{2}}{r _{1} + r _{2} + R} \times R$ (2) $\frac{E _{1} - E _{2}}{r _{1} + r _{2} + R} \times R$ (3) $\frac{E _{1} + E _{2}}{r _{1} + r _{2}} \times R$ (4) $\frac{E _{1} - E _{2}}{r _{1} + r _{2}} \times R$ 454. $Two heating coils of resistances 10Ω and 20Ω are connected in parallel and connected to a battery of emf 12 V and internal resistance 1Ω . The power consumed by them are in the ratio$ (1) $1 : 4$ (2) $1 : 3$ (3) $2 : 1$ (4) $4 : 1$ 455. $Five equal resistances each of resistance R are connected as shown in the figure. A battery of V volts is connected between A and B . The current flowing in AFCEB will be$ (1) $\frac{3 V}{R}$ (2) $\frac{V}{R}$ (3) $\frac{V}{2 R}$ (4) $\frac{2 V}{R}$ 456. $Hive current carrying conductors meet at a point ' O' as shown in figure. The magnitude and direction of the current in conductor ' OP' is$ (1) $6.5 A from O to P$ (2) $9 A from P to O$ (3) $10.5 A from P to O$ (4) $11.5 A from O to P$ 457. $A wire of resistance R is bent into a triangular pyramid as shown in figure with each segment having same length. The resistance between points A and B is R / n . The value of n is:$ (1) $16$ (2) $10$ (3) $12$ (4) $14$ 458. $A galvanometer has a resistance of 50Ω and it allows maximum current of 5 mA . It can be converted into voltmeter to measure up to 100 V by connecting in series a resistor of resistance$ (1) $5975Ω$ (2) $20050Ω$ (3) $19950Ω$ (4) $19500Ω$ 459. $In the circuits shown below, the readings of voltmeters and the ammeters will be [NEET 2019]$ (1) $V_{1} = V_{2} and I_{1} > I_{2}$ (2) $V_{1} = V_{2} and I_{1} = I_{2}$ (3) $V_{2} > V_{1} and I_{1} > I_{2}$ (4) $V_{2} > V_{1} and I_{1} = I_{2}$ 460. $Two cells of emf 2E and E with internal resistance r_{1} and r_{2} respectively are connected in series to an external resistor R (see figure). The value of R, at which the potential difference across the terminals of the first cellbecomes zero is$ (1) $r_{1} + r_{2}$ (2) $\frac{r _{1}}{2} - r_{2}$ (3) $\frac{r _{1}}{2} + r_{2}$ (4) $r_{1} - r_{2}$ 461. $In the circuit, the value of the current, I is$ (1) $1 A$ (2) $0.5 A$ (3) $0.25 A$ (4) $0.75 A$ 462. $In the above circuit the current in each resistance is:$ (1) $0 A$ (2) $1 A$ (3) $0.25 A$ (4) $0.5 A$ 463. $The resistance of the meter bridge AB in given figure is 4Ω. With a cell of emf ε = 0.5 V and rheostat resistance R_{h} = 2Ω the null point is obtained at some point J. When the cell is replaced by another one of emf ε = ε_{2} the same null point J is found for R_{h} = 6 Ω. The emf ε_{2} is:$ (1) $0.5 V$ (2) $0.3 V$ (3) $0.4 V$ (4) $0.6 V$ 464. $From resistances of 100 ohm each are connected in the form of a square. The effective resistance along the diagonal points P R is:$ (1) $100$ (2) $180$ (3) $220$ (4) $440$ 465. $A, B and C are voltmeters of resistance R, 1.5 R and 3R respectively as shown in the figure. When some potential difference is applied between X and Y, the voltmeter readings are V_{A}, V_{B} and V_{C} respectively. Then,$ (1) $V_{A} = V_{B} = V_{C}$ (2) $V_{A} \neq = V_{B} = V_{C}$ (3) $V_{A} = V_{B} \neq = V_{C}$ (4) $V_{A} \neq = V_{B} \neq = V_{C}$ 466. $A cell of emf 1.8 V gives a current of 17 A when directly connected to an ammeter of resistance 0.06Ω . Internal resistance of the cell is$ (1) $0.046Ω$ (2) $0.066Ω$ (3) $0.10Ω$ (4) $10Ω$ 467. $Two resistors of resistances 2Ω and 6Ω are connected in parallel. This combination is then connected to a battery of emf 2 V and internal resistance 0.5Ω . What is the current flowing through the battery?$ (1) $\frac{4}{17} A$ (2) $4 A$ (3) $1 A$ (4) $\frac{4}{3} A$ 468. $In the following network potential at O$ (1) $4 V$ (2) $3 V$ (3) $6 V$ (4) $4.8 V$ 469. $Three resistors 1Ω, 2Ω and 3Ω are connected to form a triangle. Across 3Ω resistor a 3 V battery is connected. The current through 3Ω resistor is$ (1) $0.75 A$ (2) $1 A$ (3) $2 A$ (4) $1.5 A$ 470. $In the circuit shown, the current in the 1Ω resistor is:$ (1) $1.3 A, from P to Q$ (2) $0 A$ (3) $0.13 A, from Q to P$ (4) $0.13 A, from P to Q$ 471. $A 12 cm wire is given a shape of a right-angled triangle ABC having sides 3 cm, 4 cm and 5 cm as shown in the figure. The resistance between two ends (AB, BC, CA) of the respective sides are measured one by one by a multimeter. The resistances will be in the ratio$ (1) $9: 16: 25$ (2) $27: 32: 35$ (3) $21 : 24 : 25$ (4) $3 : 4: 5$ 472. $A regular hexagon is formed by six wires each of resistance rΩ and the corners are joined to the centre by wires of same resistance. If the current enters at one corner and leaves at the opposite corner, the equivalent resistance of the hexagon between the two opposite corners will be$ (1) $\frac{3}{4} r$ (2) $\frac{4}{5} r$ (3) $\frac{3}{5} r$ (4) $\frac{5}{8} r$ 473. $Each of the six ideal batteries of emf 20 V is connected to an external resistance of 4Ω as shown in the figure. The current through the resistance is$ (1) $6 A$ (2) $3 A$ (3) $4 A$ (4) $None$ 474. $A uniform metallic wire has a resistance of 18Ω and isbent into an equilateral triangle. Then, the resistancebetween any two vertices of the triangle is:$ (1) $4Ω$ (2) $8Ω$ (3) $12 W$ (4) $2 W$ 475. $Two resistors 2Ω and 3Ω are connected in the gaps of bridge as shown in figure. The null point is obtained with the contact of jockey at some point on wire XY . When an unknown resistor is connected in parallel with 3Ω resistor, the null point is shifted by 22.5 cm toward Y . The resistance of unknown resistor is____Ω .$ (1) $2$ (2) $1$ (3) $4$ (4) $3$ 476. $The power dissipated in 3Ω resistance in the following circuit is$ (1) $1 W$ (2) $0, 5 W$ (3) $0.25 W$ (4) $0.75 W$ 477. $The resistance of a wire is 5 Ω . It's new resistance in ohm if stretched to 5 times of it's original length will be:$ (1) $625$ (2) $5$ (3) $125$ (4) $25$ 478. $For designing a voltmeter of range 50 V and an ammeter of range 10 mA using a galvanometer which has a coil of resistance 54Ω showing a full scale deflection for 1 mA as in figure. (A) for voltmeter R \approx 50 kΩ (B) for ammeter r\approx0.2Ω (C) for ammeter r\approx6Ω (D) for voltmeter R \approx 5 kΩ (E) for voltmeter R\approx500Ω Choose the correct answer from the options given below:$ (1) $(A) and (C)$ (2) $(C) and (E)$ (3) $(C) and (D)$ (4) $(A) and (B)$ 479. $Two batteries with e.m.f 12V and 13V are connected in parallel across a load resistor of 10Ω. The internal resistance of the two batteries are 1Ω and 2Ω respectively. The voltage across the load lies between:$ (1) $11.4V and 11.5 V$ (2) $11.7V and 11.8V$ (3) $11.6V and 11.7V$ (4) $11.5V and 11.6V$ 480. $The resistance of the meter bridge AB in given figure is 4Ω . With a cell of emf ϵ = 0.5 V and rheostat resistance R_{b} = 2Ω the null point is obtained at some point J . When the cell is replaced by another one of emf ϵ = ϵ_{2} the same null point J is found for R_{h} = 6Ω . The emf ϵ_{2} is:$ (1) $0.4 V$ (2) $0.3 V$ (3) $0.6 V$ (4) $0.5 V$