481.A filament bulb (500W,100V) is to be used in a 230 V main supply. When a resistance R is connected in series, it works perfectly, and the bulb consumes 500 W The value of R is- (1)230Ω
- (2)46Ω
- (3)26Ω
- (4)13Ω
482.A wire of resistance 12 ohms per meter is bent to form a complete circle of radius 10cm. The resistance between its two diametrically opposite points, A and B as shown in the figure is- (1)3 Ω
- (2)6πΩ
- (3)6 Ω
- (4)0.6πΩ
483.The terminal voltage of the battery, whose emf is 10 V and internal resistance 1Ω, when connected through an external resistance of 4Ω as shown in the figure is [NEET 2024]- (1)4 V
- (2)6 V
- (3)8 V
- (4)10 V
484.In the experimental set up of meter bridge shown in the figure, the null point is obtained at a distance of 40 cm from A. If a 10Ω resistor is connected in series with R1, the null point shifts by 10 cm. The resistance that should be connected in parallel with (R1 + 10) Ω such that the null point shifts back to its initial position is:- (1)60
- (2)30
- (3)20
- (4)40
485.The length of a potentiometer wires is l. A cell of emf E is balanced at a length (3l) from positive end of the wire. If the length of the wire is increased by (2l), the distance at which the same cell gives the balancing point is (Cell in the primary is ideal and no series resistance is present in the primary circuit.)- (1)32l
- (2)2l
- (3)6l
- (4)34l
486.In the circuit shown in the figure, if potential at point A is taken to be zero the potential at point B is:- (1)–1V
- (2)+ 2V
- (3)– 2V
- (4)+ 1V
487.In the given figure: V1=V,V2=αV,R1=βR,R2=γR, where α,β, and γ are positive real numbers. The value of current I is- (1)4β(β+γ)(α−1)γRV
- (2)4β(α−1)RV
- (3)2γ(β+γ)(α−1)βRV
- (4)2βγ(α−1)(β+γ)RV
488.During an experiment with a meter bridge, the galvanometer shows a null point when the joceky is pressed at 40.0 cm using a standard resistance of 90 Ω, as shown in the figure. The least count of the scale used in the meter bridge is 1 mm. The unknown resistance is- (1)60±0.15Ω
- (2)135±0.56Ω
- (3)60±0.25Ω
- (4)135±0.23Ω
489.In an ammeter 0.2% of main current passes through the galvanometer. If resistance of galvanometer is G, the resistance of ammeter will be:- (1)4991G
- (2)500499G
- (3)5001G
- (4)499500G
490.A direct current of 4 A and an alternating current of peak value 4A flow through resistance of 3Ω and 2Ω respectively. The ratio of heat produced in the two resistances in same interval of time will be:- (1)3 : 2
- (2)3 : 1
- (3)3 : 4
- (4)4: 3
491.In this circuit, when certain current flows, the heat produced in 5Ω is 4.05J in a time t. The heat produced in 2Ω coil in the same time interval is- (1)5.76
- (2)1.44
- (3)2.88
- (4)2.02
492.A potentiometer wire AB having length L and resistance 12r is joined to a cell D of emfϵ and internal resistance r. A cell C having emfϵ/2 and internal resistance 3 r is connected. The length AJ at which the galvanometer as shown in fig. shows no deflection is:- (1)1211L
- (2)2411L
- (3)2413L
- (4)125L
493.Two cells of same emf but different internal resistances r1 and r2 are connected in series with a resistance R. The value of resistance R, for which the potential difference across second cell is zero, is- (1)r2-r1
- (2)r1-r2
- (3)r1
- (4)r2
494.The current I in the given circuit will be- (1)10A
- (2)20A
- (3)4A
- (4)40A
495.In a wheatstone bridge as shown in the figure. What will be the condition for no deflection in galvanometer?- (1)PQ=S1S2R(S1+S2)
- (2)PQ=S1S2R
- (3)QP=S1S2R(S1+S2)
- (4)QP=S1+S2R
496.A battery consists of a variable number (n) of identical cells, each having an internal resistance r connected in series. The terminals of the battery are short-circuited. A graph of current (I) in the circuit verses the number of cells will be as shown in figure.- (1)
- (2)
- (3)
- (4)
497.In the following network, the current flowing through 15Ω resistance is- (1)0.8A
- (2)1.0A
- (3)1.2A
- (4)1.4A
498.Figure shows a part of an electric circuit. The potentials at points a, b and c are 30 V, 12 V and 2 V respectively. The current through the 20Ω resistor will be,- (1)1.0A
- (2)0.4 A
- (3)0.6 A
- (4)0.2 A
499.In the circuit shown, the value of I in ampere is- (1)1
- (2)0.60
- (3)0.4
- (4)1.5
500.The equivalent resistance of the circuit shown below between points a and b is:- (1)16Ω
- (2)3.2Ω
- (3)24Ω
- (4)20Ω
501.A resistance is shown in the figure. Its value and tolerance are given respectively by:- (1)270Ω,10%
- (2)27kΩ,10%
- (3)27kΩ,20%
- (4)270Ω,5%
502.Two identical batteries each of e.m.f 2V and internal resistance 1Ω are available to produce heat in an external resistance by passing a current through it. The maximum power that can be developed across R using these batteries is- (1)3.2W
- (2)2.0W
- (3)1.28W
- (4)98W
503.In the figure shown, what is the current (in Ampere) drawn from the battery? You are given: R1=15Ω,R2=10Ω,R3=20Ω,R4=5Ω,R5=25Ω,R6=30Ω,E=15V- (1)13/24
- (2)7/18
- (3)9/32
- (4)20/3
504.In the circuit, the cells are having negligible resistances. If the galvanometer shows null defection then the value of ' V ' is- (1)12V
- (2)6 V
- (3)4 V
- (4)2 V
505.The current I1 (in A) flowing through 1 Ω resistor in the following circuit is- (1)0.2
- (2)0.4
- (3)0.5
- (4)0.25
506.From the graph between current (I) and voltage (V) is shown. Identify the portion corresponding to negative resistance- (1)CD
- (2)DE
- (3)AB
- (4)BC
507.Potential difference between A and B in the following circuit- (1)4V
- (2)5.6V
- (3)2.8V
- (4)6V
508.In the circuit, given in the figure currents in different branches and value of one resistor are shown. Then potential at point B with respect to the point A is- (1)+1V
- (2)−2V
- (3)+2V
- (4)−1V
509.In the given circuit diagram, a wire is joining points B and D. The current in this wire is:- (1)1.6A
- (2)2A
- (3)2.4A
- (4)3A
510.In a wheatstone bridge (see fig.), Resistances P and Q are approximately equal. When R = 400 Ω, the bridge is balanced. On interchanging P and Q, the value of R, for balance, is 405 Ω. The value of X is close to:- (1)404.5 ohm
- (2)402.5 ohm
- (3)403.5 ohm
- (4)401.5 ohm
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