A charged particle is accelerated from rest through a certain potential difference. The de-Broglie wavelength is _1 when it is accelerated through V_1 and is _2 when accelerated through V_2. The rati…

Question

A charged particle is accelerated from rest through a certain potential difference. The de-Broglie wavelength is _1 when it is accelerated through V_1 and is _2 when accelerated through V_2. The ratio _1/ _2 is

Accepted Answer

Correct answer: B. (b) The de-Broglie wavelength ( ) associated with a charged particle is given by = hp= h 2 mE= h 2 mqV Here, h= planck's constant m= mass of charged particle q= charge on the particle V= potential at which the charged particle is accelerated. As the charge q and mass m is same in both cases. ∴ _1 _2= h mqV_1 mqV_2h = mqV_2 mqV_1= V_2V_1=V_2^ 12 V_1^ 12 .

$A charged particle is accelerated from rest through a certain potential difference. The de-Broglie wavelength is λ_{1} when it is accelerated through V_{1} and is λ_{2} when accelerated through V_{2} . The ratio λ_{1} / λ_{2} is$

Solution

More Dual Nature of Matter & Radiation PYQs