An inductor 20 mH, a capacitor 100 μF and a resistor 50 are connected in series across a source of emf ,V=10 sin314t. The power loss in the circuit is

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Correct answer: A. (a) Impedance Z in an ac circuit is Z= R^2+ (X_C-X_L )^2; where X_C= capacitive reactance and X_L= inductive reactance. Also X_C= 1 ωC and X_L= ωL Z= 50^2+( 1314 100 10^-6-314 20 10^-3)^2 or Z=56 The power loss in the circuit is P_ av= ( V_ rmsZ )^2R ∴P_ av= ( 10 ( 2 )56 )^2 50=0.79W

$An inductor 20 mH, a capacitor 100 μF and a resistor 50Ω are connected in series across a source of emf, V = 10 sin 314 t . The power loss in the circuit is$

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