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JEE · NEET Previous Year Question

$In a coil, the current changes from - 2 A to + 2 A in 0.2 s and induces an emf of 0.1 V . The self inductance of the coil is:$

Topic: JEE PYQ

Answer: C. Full step-by-step solution below.

A $4 mH$
B $1 mH$
C $5 mH$
D $2.5 mH$

Correct answer: C

Solution

(c) (Emf)_{induced} = - L \frac{di}{dt} In magnitude form, (Emf_{ind}) = ((-) L \frac{di}{dt}) mat h \Rightarrow 0.1 = \frac{( L ) ( + 2 - ( - 2 ))}{0.2} \Rightarrow L = \frac{0.1 \times 0.2}{4} = 5 m H

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