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JEE · NEET Previous Year Question

$What is the electric potential at a distance of 9 cm from 3 nC ?$

Topic: JEE PYQ

Answer: A. Full step-by-step solution below.

A $300 V$
B $270 V$
C $30 V$
D $3 V$

Correct answer: A

Solution

(a) Electric potential due to a point charge Q at a distance r from it, is V = \frac{1}{4 π ϵ _{0}} \frac{Q}{r} Here, Q = 3 nC = 3 \times 10^{- 9} C r = 9 cm = 9 \times 10^{- 2} m ∴ V = \frac{9 \times 10 ^{9} \times 3 \times 10 ^{- 9}}{9 \times 10 ^{- 2}} = 300 V

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