If 1000 droplets of water of surface tension 0.07 N/m. having same radius 1 mm each, combine to from a single drop. In the process the released surface energy is- (Take π= 2 27)

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Accepted Answer

Correct answer: B. (b) 1000 4 3 (1 )^3= 4 3R^3 R=10mm T x 1000 x 4 (10-3)2 - T x 4 (10 x 10-3)2 = E E = 4 x x 7 x 10-2 [1000 - 100] x 10-6 E = 7.92 x 10-4J

$If 1000 droplets of water of surface tension 0.07 N/m. having same radius 1 mm each, combine to from a single drop. In the process the released surface energy is- (Take π = \frac{22}{7})$

Solution

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