A meniscus drop of radius 1 cm is sprayed into 10^6 droplets of equal size. Calculate the energy expended if surface tension of mercury is 435 10^-3 N/m.

Question

Accepted Answer

Correct answer: A. (a) Given, Number of smaller droplets, n=10^6 Surface tension, T=435 10^-3 Nm^-1 Radius of meniscus, R=1 cm=10^-2 m Work done in splitting a large drop of radius R in n smaller drops of equal size is W=T Increment in surface area Here, T= surface tension. ∴ W= (4 R^2 )T .(n^1/3-1) =4 (10^-2 )^2 435 10^-3 ( (10^6 )^1/3-1) =54.1 10^-3 J

$A meniscus drop of radius 1 cm is sprayed into 10^{6} droplets of equal size. Calculate the energy expended if surface tension of mercury is 435 \times 10^{- 3} N / m .$

Solution

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