A body of volume V floats on water with 13 of its volume above the surface. The volume of the object above the surface when floating on a liquid of specific gravity 1.5 is

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Correct answer: C. (c) We have V^ 'V= l V^ '= Volume of substance inside the liquid So, 23= 1000 = 20003 kg/m^3 When, _l=1500 kg/m^3 , V^ 'V= 20003 1500 ⇒ V^ 'V= 49 ⇒V^ '= 49 V So, volume above the surface V- 49V= 59V

$A body of volume V floats on water with \frac{1}{3} of its volume above the surface. The volume of the object above the surface when floating on a liquid of specific gravity 1.5 is$

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