A body of mass 1 kg is moving with a velocity 10 ms^-1 due to a constant force on a horizontal rough surface having coefficient of kinetic friction 0.4. If the constant force is removed, the body com…

Question

A body of mass 1 kg is moving with a velocity 10 ms^-1 due to a constant force on a horizontal rough surface having coefficient of kinetic friction 0.4. If the constant force is removed, the body comes to rest in a time (Acceleration due to gravity =10 ms^-2 )

Accepted Answer

Correct answer: A. (a) Mass of body, m=1 kg velocity, v=10 m/s Coefficient of kinetic friction, =0.4 from the equation of motion v=u+ att= va ( ∵F= mg ) = vmF= vm mg= v g The body comes to rest in a time t= v g= 100.4 10=2.5 s

$A body of mass 1 kg is moving with a velocity 10 ms^{- 1} due to a constant force on a horizontal rough surface having coefficient of kinetic friction 0.4. If the constant force is removed, the body comes to rest in a time (Acceleration due to gravity = 10 ms^{- 2})$

Solution

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