Suppose the charge of a proton and an electron differ slightly. One of them is – e, the other is (e + De). If the net of electrostatic force and gravitational force between two hydrogen atoms placed…

Question

Suppose the charge of a proton and an electron differ slightly. One of them is – e, the other is (e + De). If the net of electrostatic force and gravitational force between two hydrogen atoms placed at a distance d (much greater than atomic size) apart is zero, then De is of the order of [Given mass of hydrogen m_h = 1.67 × 10^–27 kg

Accepted Answer

Correct answer: C. (c) Net Charge on one H-atom = –e + (e + De) = De Net electrostatic force between two H-atoms = k ( e ) ( e )d^2 repulsive Net gravitational force between two H-atoms = G (m ) (m )d^2 For equal magnitude k ( e )^2d^2= Gm^2d^2 De2 = Gm^2k = (6.67 10^ –11 ) (1.67 10^ –27 )^2 (9 10^9 ) De2 is of the order of 10–74 De is of the order of 10–37

Solution

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