A black body of surface area 10cm^2 is heated to 127°C and is suspended in a room at temperature 27°C. The initial rate of loss of heat from the body at the room temperature will be

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Correct answer: D. (d) Loss of heat Q=A (T^4-T_0^4 )t ⇒ Rate of loss of heat Qt=A (T^4-T_0^4 ) =10 10^-4 1 5.67 10^-8\273+127 )^4- (273+27 )^4\ = 0.99 W.

$A black body of surface area 10 c m^{2} is heated to 127°C and is suspended in a room at temperature 27°C. The initial rate of loss of heat from the body at the room temperature will be$

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