The speed of a particle changes from 5 ms^-1 to 2 5 ms^-1 in a time t. If the magnitude of change in its velocity is 5 ms^-1, the angle between the initial and final velocities of the particle is

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Accepted Answer

Correct answer: D. (d) Given initial velocity, v_i= 5 ms^-1 Final velocity, v_f=2 5 ms^-1 and R^2=A^2+B^2+2 ABcos ⁡ cos ⁡ = v^2-v_i^2-v_f^22v_iv_f ⇒ cos ⁡ = (5 )^2- ( 5 )^2- (2 5 )^22 ( 5 ) ( 5 ) ⇒ cos ⁡ = 25-5-2010= 010=0 ⇒ =90^ Hence, the correct option is (d).

$The speed of a particle changes from 5 ms^{- 1} to 25 ms^{- 1} in a time t . If the magnitude of change in its velocity is 5 ms^{- 1}, the angle between the initial and final velocities of the particle is$

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