If the temperature of a gas is increased from 27^ C to 159^ C, then the percentage increase in the rms speed of the gas molecules is

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Accepted Answer

Correct answer: D. (d) V_ rms= 3 RTM At27^ C=27+273=300 K ∴V_ rms_1= 3R (300 )M andV_ ms_2= 3R (432 )M atT^ '= .159+273=432 ∴ Percentage increase in the rms speed = ( V_ mms_2-V_ rms_1 V_ ms_1 ) 100 = 3RM ( 432- 300 ) 3RM ( 300 ) 100= ( 20.78-17.3217.32 ) 100=20 \%

$If the temperature of a gas is increased from 27^{\circ} C to 159^{\circ} C, then the percentage increase in the rms speed of the gas molecules is$

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