An ideal gas in a container of volume 500 c.c. is at a pressure of 2 10^+5 N/m^2. The average kinetic energy of each molecules is 6 10^-21 J. The number of gas molecules in the container is

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Correct answer: D. (d) : V=500 cc ,P=2 10^5 N/m^2 , KE=6 10^-21 J PV=NK_BT KE molecule= 32K_BT= 32 PVN from equation (i) N= 32 PV KE molecule N= 32 2 10^5 500 10^-66 10^-21=2.5 10^22

$An ideal gas in a container of volume 500 c.c. is at a pressure of 2 \times 10^{+ 5} N / m^{2} . The average kinetic energy of each molecules is 6 \times 10^{- 21} J . The number of gas molecules in the container is$

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