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JEE · NEET Previous Year Question

$The equation of state for 2 g of oxygen at a pressure P and temperature T, when occupying a volume V will be$

Topic: JEE PYQ

Answer: C. Full step-by-step solution below.

A $PV = 16 RT$
B $PV = RT$
C $PV = \frac{1}{16} RT$
D $PV = 2 RT$

Correct answer: C

Solution

(c) : Here given, mass of oxygen m_{O_{2}} = 2 g ∴ n = \frac{m _{O_{2}}}{M} = \frac{2}{32} = \frac{1}{16} ∴ Equation of state will be, PV = nRT = \frac{1}{16} RT

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