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JEE · NEET Previous Year Question

$The molecular mass of a gas having r.m.s. speed four times as that of another gas having molecular mass 32 is$

Topic: JEE PYQ

Answer: A. Full step-by-step solution below.

A $2$
B $4$
C $16$
D $32$

Correct answer: A

Solution

(a) : Given, v_{2} = v, v_{1} = 4 v, M_{2} = 32, M_{1} = ? v_{rms} \propto \frac{1}{M} \frac{v _{2}}{v _{1}} = \frac{M _{1}}{M _{2}} \Rightarrow \frac{v}{4 v} = \frac{M _{1}}{32} \frac{1}{16} = \frac{M _{1}}{32} \Rightarrow M_{1} = 2

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