A solid metal cube of edge length 2 cm is moving in a positive y -direction at a constant speed of 6m/s. There is a uniform magnetic field of 0.1T in the positive z -direction. The potential differen…

Question

A solid metal cube of edge length 2 cm is moving in a positive y -direction at a constant speed of 6m/s. There is a uniform magnetic field of 0.1T in the positive z -direction. The potential difference between the two faces of the cube perpendicular to the x -axis, is:

Accepted Answer

Correct answer: A. (a) JEE Main 2019 Potential difference between two faces perpendicular to x -axis = λV B=2 10^-2(6 0.1)=12mV

$A solid metal cube of edge length 2 cm is moving in a positive y -direction at a constant speed of 6 m/s. There is a uniform magnetic field of 0.1 T in the positive z -direction. The potential difference between the two faces of the cube perpendicular to the x -axis, is:$

Solution

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