What will be the nature of flow of water from a circular tap, when its flow rate increased from 0. 18L min to 0. 48L min ? The radius of the tap and viscosity of water are 0.5 cm and 10^-3 Pas, respe…

Question

What will be the nature of flow of water from a circular tap, when its flow rate increased from 0. 18L min to 0. 48L min ? The radius of the tap and viscosity of water are 0.5 cm and 10^-3 Pas, respectively.(Density of water : ( : 10^3 kgm^3 )

Accepted Answer

Correct answer: D. (d) JEE Main 2021 The nature of flow is determined by Reynolds Number. R_e= ρvD ( \& density of fluid ; coefficient of \&v velocity of flow \&D Diameter of pipe) From NCERT IfR_e<1000 flow is steady 1000<R_e<2000 flow becomes unsteady R_e>2000 flow is turbulent R_ einitial=10^3 0.18 10^-3 (0.5 10^-2)^2 60 1 10^-210^-3 =382.16 R_e final=10^3 0.48 10^-3 (0.5 10^-2)^2 60 1 10^-210^-3 =1019.09

$What will be the nature of flow of water from a circular tap, when its flow rate increased from 0. \frac{18 L}{min} to 0. \frac{48 L}{min} ? The radius of the tap and viscosity of water are 0.5 cm and 10^{- 3} Pas, respectively.(Density of water : (: \frac{10 ^{3} kg}{m ^{3}})$

Solution

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