The de-Broglie wavelength of a particle having kinetic energy E is λ. How much extra energy must be given to this particle so that the de-Broglie wavelength reduces to 75% of the initial value?

Question

Accepted Answer

Correct answer: B. (b) = h mv= h 2 mE , mv= 2 mE ∝ 1 E _2 _1= E_1E_2= 34 , _2=0.75 _1 E_1E_2= ( 34 )^2 E_2= 169E_1= 169E(E_1=E) Extra energy given = 169E-E= 79E

$The de-Broglie wavelength of a particle having kinetic energy E is λ . How much extra energy must be given to this particle so that the de-Broglie wavelength reduces to 75% of the initial value?$

Solution

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