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JEE · NEET Previous Year Question

$A wire of length 40 cm is stretched by 0.1 cm . The strain on the wire is$

Topic: JEE PYQ

Answer: A. Full step-by-step solution below.

A $25 \times 10^{- 4}$
B $40 \times 10^{- 4}$
C $10 \times 10^{- 4}$
D $12.5 \times 10^{- 4}$

Correct answer: A

Solution

(a) Strain = \frac{Δ l}{l} = \frac{0.1}{40} = 25 \times 10^{- 4} cm

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