What is the work done in stretching a uniform metal wire of length from 2 m to 2.004 m with an area of cross section 10^-6 m^2 ? [Young's modulus of the wire =2 10^11 N/m^2 ]

Question

Accepted Answer

Correct answer: B. (b) ll= 22 10^-3=10^-3 Stress =Y strain =2 10^11 10^-3 =2 10^8 Nm^2 Volume =4 10^-6 2=8 10^-6m^3 Energy stored = 12 stress strain volume = 12 2 10^8 10^-3 8 10^-6=0.8J

$What is the work done in stretching a uniform metal wire of length from 2 m to 2.004 m with an area of cross section 10^{- 6} m^{2} ? [Young's modulus of the wire = 2 \times 10^{11} N / m^{2}]$

Solution

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