A galvanometer of resistance 50 gives a full scale deflection for a current 5 10^-4 A. The resistance that should be connected in series with the galvanometer to read 3 V is

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Correct answer: B. (b) Here, Resistance of galvanometer, G=50 Current for full scale deflection, I_g=5 10^-4 A Let R be resistance connected in series with the galvanometer to read 3 V. Then V=I_g (G+R ) or R= VI_g-G R= 3 V5 10^-4 A-50 6000 50 =5950

$A galvanometer of resistance 50Ω gives a full scale deflection for a current 5 \times 10^{- 4} A . The resistance that should be connected in series with the galvanometer to read 3 V is$

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