The ratio of resolving powers of an optical microscope for two wavelengths λ_1=4 0 0 0 A^ and λ_2=6 0 0 0 A^ is

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Correct answer: B. (b): The resolving power of an optical microscope, R P= 2 μ s i n θλ For wavelength λ_1=4 0 0 0 A^ , resolving power will be R P_1= 2 μ s i n θ4 0 0 0… (i) For wavelength λ_2=6 0 0 0 Å , resolving power will be R P_2= 2 μ s i n g q6 0 0 0(ii) On dividing eqn. (i) by eqn. (ii) R P_1R P_2= 6 0 0 04 0 0 0= 32

$The ratio of resolving powers of an optical microscope for two wavelengths λ_{1} = 4000 A^{\circ} and λ_{2} = 6000 A^{\circ} is$

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