The aperture diameter of a telescope is 5m. The separation between the moon and the earth is 4 × 10^5 km. With light of wavelength of 5500 Å, the minimum separation between objects on the surface of…

Question

The aperture diameter of a telescope is 5m. The separation between the moon and the earth is 4 × 10^5 km. With light of wavelength of 5500 Å, the minimum separation between objects on the surface of moon, so that they are just resolved, is close to :

Accepted Answer

Correct answer: D. (d) θ = 1.22 λa distance = O_1O_2 = dθ = 1.22 λad distance = O_1O_2 = 1.22×5893×10^−10×4×10^85 ≈ 57.5 m ∴ answer from options = 60m (minimum distance )

$The aperture diameter of a telescope is 5m. The separation between the moon and the earth is 4 \times 1 0^{5} km. With light of wavelength of 5500 Å, the minimum separation between objects on the surface of moon, so that they are just resolved, is close to :$

Solution

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