If we need a magnification of 375 from a compound microscope of tube length 150 mm and an objective of focal length 5 mm , the focal length of the eye-piece, should be close to:

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Accepted Answer

Correct answer: B. (b)JEE Main 2020 Case- I If final image is at least distance of clear vision M.P. = Lf_0(1+ Df_e) ;375= 1505(1+ 25f_e) 37530=1+ 25f_e 34530= 25f_e f_e= 750345=2.17 cm ;f_e ≈22 mm Case- II If final image is at infinity M.P. = Lf_0 ( Df_e )=375 f_e=22 mm

$If we need a magnification of 375 from a compound microscope of tube length 150 mm and an objective of focal length 5 mm, the focal length of the eye-piece, should be close to:$

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