JEE · NEET Previous Year Question
The magnifying power of a telescope is 9. When it is adjusted for parallel rays the distance between the objective and eyepiece is 20 cm. The focal length of lenses are :
Topic: NEET PYQ
Answer: C. Full step-by-step solution below.
- A10 cm, 10 cm
- B15 cm, 5 cm
- C18 cm, 2 cm
- D11 cm, 9 cm
Correct answer: C
Solution
(c)M.P = g = .........(b)f0 + fe = 20 .........(a)
on solving f0 = 18 cm
fe = 2 cm
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