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JEE · NEET Previous Year Question

$A telescope has magnifying power 5 and length of tube is 60 cm then the focal length of eye piece is$

Topic: JEE PYQ

Answer: A. Full step-by-step solution below.

A $10 cm$
B $20 cm$
C $30 cm$
D $40 cm$

Correct answer: A

Solution

(a)JEE Main 2020 m = \frac{f _{0}}{f _{e}} 5 = \frac{f _{0}}{f _{e}} f_{0} = 5 f_{e} f_{0} + f_{e} = 60 6 f_{e} = 60 f_{e} = 10

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